(8x^12y^-3/y^6z^3)^-4/3

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Solution for (8x^12y^-3/y^6z^3)^-4/3 equation: 


D( x )

((8*x^12*y^-3)/(y^6))*z^3 = 0

y^6 = 0

((8*x^12*y^-3)/(y^6))*z^3 = 0

((8*x^12*y^-3)/(y^6))*z^3 = 0

8*x^12*y^-9*z^3 = 0 // : 8*y^-9*z^3

x^12 = 0

x = 0

y^6 = 0

y^6 = 0

y^6 = 0

x naleu017Cy do R

x belongs to the empty set

((((8*x^12*y^-3)/(y^6))*z^3)^-4)/3 = 0

x belongs to the empty set

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